الاجابة
x6 – 64 = (x2)3 – (4)3
=[(x2)2 + 4(x2) + (4)2] (x2 – 4)
(x + 2)(x – 2)(x4 + 4x2 + 16) =
(x +2)(x – 2)(x2 + 2x + 4)(x2 – 2x +4) =